x^2-4x+20=5

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Solution for x^2-4x+20=5 equation: 


Simplifying
x2 + -4x + 20 = 5

Reorder the terms:
20 + -4x + x2 = 5

Solving
20 + -4x + x2 = 5

Solving for variable 'x'.

Reorder the terms:
20 + -5 + -4x + x2 = 5 + -5

Combine like terms: 20 + -5 = 15
15 + -4x + x2 = 5 + -5

Combine like terms: 5 + -5 = 0
15 + -4x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-15' to each side of the equation.
15 + -4x + -15 + x2 = 0 + -15

Reorder the terms:
15 + -15 + -4x + x2 = 0 + -15

Combine like terms: 15 + -15 = 0
0 + -4x + x2 = 0 + -15
-4x + x2 = 0 + -15

Combine like terms: 0 + -15 = -15
-4x + x2 = -15

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -15 + 4

Reorder the terms:
4 + -4x + x2 = -15 + 4

Combine like terms: -15 + 4 = -11
4 + -4x + x2 = -11

Factor a perfect square on the left side:
(x + -2)(x + -2) = -11

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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